...maths...?

1) A map shows three towns A.B and C. Town A is due North of C. town B is due East of A. The distance Ac is 75km and the bearing of C from B is 245 degree. Calculate giving the answer to the nearest 100m:


(a) The distance AB


(b) The distance BC








2)Two boats X and Y, sailing in the race. Boat X is 145 due North of buoy B. Boat Y is due East of buoy B. Boat X and Y are 320m apart calculate:


(a) the distance BY


(b) the bearing of Y and X


(c) the bearing of X and Y

...maths...?
75 / sin 245* = X / sin25* So X(sin 245*) = 75(sin 25*) Then X =75(sin25*) / sin 245* Either using a chart or calculator do the rest. * = degrees. To figure BY you use the Pythagorean Therom which is A^2 + B^2 = C^2 or 320^2 = 145^2 + X^2 or approx 285 m 320/sin 90* = 285(sin x*) 320/ sin 90* =285 / sin x* 320 / 285 (sin 90*) = 1/ sin x* 320 (sin x*) / 285 (sin 90*) = 1 again use a chart or calc. to do the rest
Reply:A is the anwer of 1


2


a around 100 m


b 85


c 125