1. The point at which carbon-14 will no longer be taken up by a living organism is
a. death
b. decomposition
c. illness
d. death
2. The study of charged radioactive decay particles that pass through a mineral's lattice structure is called:
a. isotopic mapping
b. atomic clock dating
c. fission track dating
d. radiometric dating
3. The only sub-atomic particle to be excluded from calculations of the mass of an atom is the
a. positron
b. proton
c. electron
d. neutron
4. Rutherford and Boltwood first used the principles of radioactive decay to date a rock using uranium, which decayed to
a. plutonium
b. lead
c. helium
d. thorium
TO ALL CHEMISTS .. Help me with these multiple choice and get 5 stars...?
1. A and D are both death and both correct.
2. D
3.A
4. D
Reply:q 3 is a.....
wisteria
Monday, May 24, 2010
Please help, math homework problem.?
I need help w/this prob.
You are on a trip to one of the cartesian islands. In the cellar of your cabin you have found an old map that claims to hold the secret location of buried treasure. The map shows four trees at location A, B, C, %26amp; D. The trees A %26amp; D are along an east-west road running through island. The tree at B is directly north of the tree at A, and the tree at C is directly north of the tree at D.
The maps directions say to trace a path from the tree at B to the tree at D, and to do the same for the trees at A and C. The treasure is buried halfwy between the intersection of these paths (point E) %26amp; the road. Because 3 small lakes dot the island, you r only able to measure the distances between B and D, A and C, %26amp; A%26amp;D:
B to D=300 paces
A to C=260 paces
A to D=240 paces
To find the location of th treasure you must find the distance from E to teh road %26amp; then walk 1/2 that distance from E. How far is E from the road %26amp; how far is is E from the buried treasure?
TY
Please help, math homework problem.?
Draw extra lines, think outside the box as to how you can make right triangles. Use the numbers provided and draw a graph as close to scale as you can (In other words, make sure the dist from A to D looks longer than the dist from A to B. This will help you visualize. Then draw lines that can help you form right triangles (especially those that have two know lengths) use the pythagorean theorum and that should give you some help. Start by extending the D to C line further north until it is exactly east of point B. This new point we'll call F. Now you can figure out B to C because you know C to F is exactly 80. (A to B minus D to C) C to F is 80, B to F is 240 which makes B to C 253. It'll take some time, but you'll get it.
Reply:what grade is that? and i really dunno...
Reply:What is your teachers contact info? Cause ima tell her you are cheating!!!
Reply:uh...i dunno sry
You are on a trip to one of the cartesian islands. In the cellar of your cabin you have found an old map that claims to hold the secret location of buried treasure. The map shows four trees at location A, B, C, %26amp; D. The trees A %26amp; D are along an east-west road running through island. The tree at B is directly north of the tree at A, and the tree at C is directly north of the tree at D.
The maps directions say to trace a path from the tree at B to the tree at D, and to do the same for the trees at A and C. The treasure is buried halfwy between the intersection of these paths (point E) %26amp; the road. Because 3 small lakes dot the island, you r only able to measure the distances between B and D, A and C, %26amp; A%26amp;D:
B to D=300 paces
A to C=260 paces
A to D=240 paces
To find the location of th treasure you must find the distance from E to teh road %26amp; then walk 1/2 that distance from E. How far is E from the road %26amp; how far is is E from the buried treasure?
TY
Please help, math homework problem.?
Draw extra lines, think outside the box as to how you can make right triangles. Use the numbers provided and draw a graph as close to scale as you can (In other words, make sure the dist from A to D looks longer than the dist from A to B. This will help you visualize. Then draw lines that can help you form right triangles (especially those that have two know lengths) use the pythagorean theorum and that should give you some help. Start by extending the D to C line further north until it is exactly east of point B. This new point we'll call F. Now you can figure out B to C because you know C to F is exactly 80. (A to B minus D to C) C to F is 80, B to F is 240 which makes B to C 253. It'll take some time, but you'll get it.
Reply:what grade is that? and i really dunno...
Reply:What is your teachers contact info? Cause ima tell her you are cheating!!!
Reply:uh...i dunno sry
Some simple questions about the astronomy,big bonus return!?
1.Consider the end of a star's life. If it is like our sun, it will finish burning off hydrogen, blow off its envelope, and leave a carbon core that is hot but not nearly as luminous as the giant stage previously. These objects are called:
a eclipsing binary stars. b. supernovae. c white dwarfs. d. brown dwarfs.
2Which is NOT used by astronomers to trace out the spiral structure of the Galaxy?
a. K and M stars. b. H II regions. c Giant molecular clouds. d. O and B stars.
3.Which part of the Galaxy contains many old Population I stars?
a. Nuclear bulge. b. Spiral arms. c. Halo. d Core.
4.How do we map out the structure and size of the arms in our galaxy?
a. Using a space probe at the galactic centre.
b. With a Norton's Star Atlas.
c. Using the observation of Cepheid Variable stars.
d. With observations of globular clusters
5.The rotation curves of distant spiral galaxies let astronomers measure their:
a. red shift. b. distance. c. age. d. mass distribution
Some simple questions about the astronomy,big bonus return!?
1. c
2. a
3. a, c, d
4. c
5. d
Reply:Cash talks
a eclipsing binary stars. b. supernovae. c white dwarfs. d. brown dwarfs.
2Which is NOT used by astronomers to trace out the spiral structure of the Galaxy?
a. K and M stars. b. H II regions. c Giant molecular clouds. d. O and B stars.
3.Which part of the Galaxy contains many old Population I stars?
a. Nuclear bulge. b. Spiral arms. c. Halo. d Core.
4.How do we map out the structure and size of the arms in our galaxy?
a. Using a space probe at the galactic centre.
b. With a Norton's Star Atlas.
c. Using the observation of Cepheid Variable stars.
d. With observations of globular clusters
5.The rotation curves of distant spiral galaxies let astronomers measure their:
a. red shift. b. distance. c. age. d. mass distribution
Some simple questions about the astronomy,big bonus return!?
1. c
2. a
3. a, c, d
4. c
5. d
Reply:Cash talks
Can anyone help me please?
The scale on a map reads 4 cm = 30 miles. If the actual distance between two cities is 120 miles, what is the distance on the map?
A) 8 cm
B) 16 cm
C) 12 cm
D) 24 cm
Can anyone help me please?
The answer is B
4/30 = x/120
30x=480
480/30=16
x=16
Reply:4 cm=30 miles
120 miles = x
4/x=30/120
30x=480
30x=30=480/30
x=16 cm
Reply:Eh. you should be asking why the answer is what it is. B is the right answer, but because you have to cross multiply using a proportion. 4 = 30, 8 = 60, 16 = 120. Just doubled the values twice, or u can put then into a proportion/cross multiply...
Reply:16 cm. 120/30 = 4, 4 x 4 = 16
Reply:B
Reply:The answer is B.
Think about it: 4 cm = 30 miles.
Therefore 8 cm = 60 miles.
12 cm = 90 miles
16 cm = 120 miles
See? What grade are you in? You should have been able to figure that out. That is 2nd grade work.
Reply:The answer is 16 cm. 120m is four times thirty, so four times 4cm is 16.
A) 8 cm
B) 16 cm
C) 12 cm
D) 24 cm
Can anyone help me please?
The answer is B
4/30 = x/120
30x=480
480/30=16
x=16
Reply:4 cm=30 miles
120 miles = x
4/x=30/120
30x=480
30x=30=480/30
x=16 cm
Reply:Eh. you should be asking why the answer is what it is. B is the right answer, but because you have to cross multiply using a proportion. 4 = 30, 8 = 60, 16 = 120. Just doubled the values twice, or u can put then into a proportion/cross multiply...
Reply:16 cm. 120/30 = 4, 4 x 4 = 16
Reply:B
Reply:The answer is B.
Think about it: 4 cm = 30 miles.
Therefore 8 cm = 60 miles.
12 cm = 90 miles
16 cm = 120 miles
See? What grade are you in? You should have been able to figure that out. That is 2nd grade work.
Reply:The answer is 16 cm. 120m is four times thirty, so four times 4cm is 16.
Help me with some math questions.. TOTALLY important grade 9 math questions?
1. A map is drawn using a scale of 4 cm to represent 5 km
a) find the representative fraction
b) A road has a length of 9.4 cm on the map, find its actual distance in km
c) A lake has an area of 64 km*2 find its area represented on the map
2. a cylindrical container of radius 8 cm contains water to a height of 5 cm. Th water in this cylinder is then poured into another cylinder of radius 5 cm. what is the height of the water in the second cylinder?
3. the length and breadth of a rectangle are (2x+1)cm and (x-1)cm respectively. If the area of the rectangle is 90cm*2, form an equation in x and hence calculate the value of x.
just the answers will do,thanks so much you'll really help this is totally important
Help me with some math questions.. TOTALLY important grade 9 math questions?
"Just the answers will do"???????????????
Please do your own homework. If you don't know how to do it- asking for help with that would be more appropriate.
Reply:1.a.the representative fraction is :
1:1.25(i.e.,1cm=5/4km)
b.1 cm on the map is 1.25km
therefore, 9.4cm on the map is
9.4*1.25=11.75km
c.64km^2=%26gt;a square of sides 8 km each
8 km in the map will be
0.8*8=6.4 cm.
therefore a square with sides 6.4 cm is to be drawn
2. the volume in the first cylinder is equal to the volume in the
second cylinder.
pi*8*8*5=pi*5*5*h
320=25h
h=12.8cm
3.(2x+1)(x-1)=90
2x^2-x-91=0
x=7,(-26/4)
Reply:1 a) 4cm/5km=4cm/500000cm=1/125000 it is unitless
b) 9.4x125000cm or 9.4x1.25km=11.75km
c) 64=8x8/1.25x1.25=7.04cm*2
2.V1=pie X r*2 X h =3.14x64x5=1004.8cum
hence 1004.8=pie X r'*2 Xh
1004.8=3.14x25xh
h=1004.8/3.14x25
=100480/7850
=12.8cm
3. A= (2x+1)(x-1)=90
=2x*2-x-91=0
x=7
anemone
a) find the representative fraction
b) A road has a length of 9.4 cm on the map, find its actual distance in km
c) A lake has an area of 64 km*2 find its area represented on the map
2. a cylindrical container of radius 8 cm contains water to a height of 5 cm. Th water in this cylinder is then poured into another cylinder of radius 5 cm. what is the height of the water in the second cylinder?
3. the length and breadth of a rectangle are (2x+1)cm and (x-1)cm respectively. If the area of the rectangle is 90cm*2, form an equation in x and hence calculate the value of x.
just the answers will do,thanks so much you'll really help this is totally important
Help me with some math questions.. TOTALLY important grade 9 math questions?
"Just the answers will do"???????????????
Please do your own homework. If you don't know how to do it- asking for help with that would be more appropriate.
Reply:1.a.the representative fraction is :
1:1.25(i.e.,1cm=5/4km)
b.1 cm on the map is 1.25km
therefore, 9.4cm on the map is
9.4*1.25=11.75km
c.64km^2=%26gt;a square of sides 8 km each
8 km in the map will be
0.8*8=6.4 cm.
therefore a square with sides 6.4 cm is to be drawn
2. the volume in the first cylinder is equal to the volume in the
second cylinder.
pi*8*8*5=pi*5*5*h
320=25h
h=12.8cm
3.(2x+1)(x-1)=90
2x^2-x-91=0
x=7,(-26/4)
Reply:1 a) 4cm/5km=4cm/500000cm=1/125000 it is unitless
b) 9.4x125000cm or 9.4x1.25km=11.75km
c) 64=8x8/1.25x1.25=7.04cm*2
2.V1=pie X r*2 X h =3.14x64x5=1004.8cum
hence 1004.8=pie X r'*2 Xh
1004.8=3.14x25xh
h=1004.8/3.14x25
=100480/7850
=12.8cm
3. A= (2x+1)(x-1)=90
=2x*2-x-91=0
x=7
anemone
...maths...?
1) A map shows three towns A.B and C. Town A is due North of C. town B is due East of A. The distance Ac is 75km and the bearing of C from B is 245 degree. Calculate giving the answer to the nearest 100m:
(a) The distance AB
(b) The distance BC
2)Two boats X and Y, sailing in the race. Boat X is 145 due North of buoy B. Boat Y is due East of buoy B. Boat X and Y are 320m apart calculate:
(a) the distance BY
(b) the bearing of Y and X
(c) the bearing of X and Y
...maths...?
75 / sin 245* = X / sin25* So X(sin 245*) = 75(sin 25*) Then X =75(sin25*) / sin 245* Either using a chart or calculator do the rest. * = degrees. To figure BY you use the Pythagorean Therom which is A^2 + B^2 = C^2 or 320^2 = 145^2 + X^2 or approx 285 m 320/sin 90* = 285(sin x*) 320/ sin 90* =285 / sin x* 320 / 285 (sin 90*) = 1/ sin x* 320 (sin x*) / 285 (sin 90*) = 1 again use a chart or calc. to do the rest
Reply:A is the anwer of 1
2
a around 100 m
b 85
c 125
(a) The distance AB
(b) The distance BC
2)Two boats X and Y, sailing in the race. Boat X is 145 due North of buoy B. Boat Y is due East of buoy B. Boat X and Y are 320m apart calculate:
(a) the distance BY
(b) the bearing of Y and X
(c) the bearing of X and Y
...maths...?
75 / sin 245* = X / sin25* So X(sin 245*) = 75(sin 25*) Then X =75(sin25*) / sin 245* Either using a chart or calculator do the rest. * = degrees. To figure BY you use the Pythagorean Therom which is A^2 + B^2 = C^2 or 320^2 = 145^2 + X^2 or approx 285 m 320/sin 90* = 285(sin x*) 320/ sin 90* =285 / sin x* 320 / 285 (sin 90*) = 1/ sin x* 320 (sin x*) / 285 (sin 90*) = 1 again use a chart or calc. to do the rest
Reply:A is the anwer of 1
2
a around 100 m
b 85
c 125
Team Fortress 2 ... ?
What's your favorite map and why ?
I like 2Fort b/c I like being an engineer and that map has the best places to put those machines ! It's awesome b/c they never see it coming .. haha !
Team Fortress 2 ... ?
Dustbowl
cause its a bowl full of dust !
I like 2Fort b/c I like being an engineer and that map has the best places to put those machines ! It's awesome b/c they never see it coming .. haha !
Team Fortress 2 ... ?
Dustbowl
cause its a bowl full of dust !
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