1. The point at which carbon-14 will no longer be taken up by a living organism is
a. death
b. decomposition
c. illness
d. death
2. The study of charged radioactive decay particles that pass through a mineral's lattice structure is called:
a. isotopic mapping
b. atomic clock dating
c. fission track dating
d. radiometric dating
3. The only sub-atomic particle to be excluded from calculations of the mass of an atom is the
a. positron
b. proton
c. electron
d. neutron
4. Rutherford and Boltwood first used the principles of radioactive decay to date a rock using uranium, which decayed to
a. plutonium
b. lead
c. helium
d. thorium
TO ALL CHEMISTS .. Help me with these multiple choice and get 5 stars...?
1. A and D are both death and both correct.
2. D
3.A
4. D
Reply:q 3 is a.....
wisteria
Monday, May 24, 2010
Please help, math homework problem.?
I need help w/this prob.
You are on a trip to one of the cartesian islands. In the cellar of your cabin you have found an old map that claims to hold the secret location of buried treasure. The map shows four trees at location A, B, C, %26amp; D. The trees A %26amp; D are along an east-west road running through island. The tree at B is directly north of the tree at A, and the tree at C is directly north of the tree at D.
The maps directions say to trace a path from the tree at B to the tree at D, and to do the same for the trees at A and C. The treasure is buried halfwy between the intersection of these paths (point E) %26amp; the road. Because 3 small lakes dot the island, you r only able to measure the distances between B and D, A and C, %26amp; A%26amp;D:
B to D=300 paces
A to C=260 paces
A to D=240 paces
To find the location of th treasure you must find the distance from E to teh road %26amp; then walk 1/2 that distance from E. How far is E from the road %26amp; how far is is E from the buried treasure?
TY
Please help, math homework problem.?
Draw extra lines, think outside the box as to how you can make right triangles. Use the numbers provided and draw a graph as close to scale as you can (In other words, make sure the dist from A to D looks longer than the dist from A to B. This will help you visualize. Then draw lines that can help you form right triangles (especially those that have two know lengths) use the pythagorean theorum and that should give you some help. Start by extending the D to C line further north until it is exactly east of point B. This new point we'll call F. Now you can figure out B to C because you know C to F is exactly 80. (A to B minus D to C) C to F is 80, B to F is 240 which makes B to C 253. It'll take some time, but you'll get it.
Reply:what grade is that? and i really dunno...
Reply:What is your teachers contact info? Cause ima tell her you are cheating!!!
Reply:uh...i dunno sry
You are on a trip to one of the cartesian islands. In the cellar of your cabin you have found an old map that claims to hold the secret location of buried treasure. The map shows four trees at location A, B, C, %26amp; D. The trees A %26amp; D are along an east-west road running through island. The tree at B is directly north of the tree at A, and the tree at C is directly north of the tree at D.
The maps directions say to trace a path from the tree at B to the tree at D, and to do the same for the trees at A and C. The treasure is buried halfwy between the intersection of these paths (point E) %26amp; the road. Because 3 small lakes dot the island, you r only able to measure the distances between B and D, A and C, %26amp; A%26amp;D:
B to D=300 paces
A to C=260 paces
A to D=240 paces
To find the location of th treasure you must find the distance from E to teh road %26amp; then walk 1/2 that distance from E. How far is E from the road %26amp; how far is is E from the buried treasure?
TY
Please help, math homework problem.?
Draw extra lines, think outside the box as to how you can make right triangles. Use the numbers provided and draw a graph as close to scale as you can (In other words, make sure the dist from A to D looks longer than the dist from A to B. This will help you visualize. Then draw lines that can help you form right triangles (especially those that have two know lengths) use the pythagorean theorum and that should give you some help. Start by extending the D to C line further north until it is exactly east of point B. This new point we'll call F. Now you can figure out B to C because you know C to F is exactly 80. (A to B minus D to C) C to F is 80, B to F is 240 which makes B to C 253. It'll take some time, but you'll get it.
Reply:what grade is that? and i really dunno...
Reply:What is your teachers contact info? Cause ima tell her you are cheating!!!
Reply:uh...i dunno sry
Some simple questions about the astronomy,big bonus return!?
1.Consider the end of a star's life. If it is like our sun, it will finish burning off hydrogen, blow off its envelope, and leave a carbon core that is hot but not nearly as luminous as the giant stage previously. These objects are called:
a eclipsing binary stars. b. supernovae. c white dwarfs. d. brown dwarfs.
2Which is NOT used by astronomers to trace out the spiral structure of the Galaxy?
a. K and M stars. b. H II regions. c Giant molecular clouds. d. O and B stars.
3.Which part of the Galaxy contains many old Population I stars?
a. Nuclear bulge. b. Spiral arms. c. Halo. d Core.
4.How do we map out the structure and size of the arms in our galaxy?
a. Using a space probe at the galactic centre.
b. With a Norton's Star Atlas.
c. Using the observation of Cepheid Variable stars.
d. With observations of globular clusters
5.The rotation curves of distant spiral galaxies let astronomers measure their:
a. red shift. b. distance. c. age. d. mass distribution
Some simple questions about the astronomy,big bonus return!?
1. c
2. a
3. a, c, d
4. c
5. d
Reply:Cash talks
a eclipsing binary stars. b. supernovae. c white dwarfs. d. brown dwarfs.
2Which is NOT used by astronomers to trace out the spiral structure of the Galaxy?
a. K and M stars. b. H II regions. c Giant molecular clouds. d. O and B stars.
3.Which part of the Galaxy contains many old Population I stars?
a. Nuclear bulge. b. Spiral arms. c. Halo. d Core.
4.How do we map out the structure and size of the arms in our galaxy?
a. Using a space probe at the galactic centre.
b. With a Norton's Star Atlas.
c. Using the observation of Cepheid Variable stars.
d. With observations of globular clusters
5.The rotation curves of distant spiral galaxies let astronomers measure their:
a. red shift. b. distance. c. age. d. mass distribution
Some simple questions about the astronomy,big bonus return!?
1. c
2. a
3. a, c, d
4. c
5. d
Reply:Cash talks
Can anyone help me please?
The scale on a map reads 4 cm = 30 miles. If the actual distance between two cities is 120 miles, what is the distance on the map?
A) 8 cm
B) 16 cm
C) 12 cm
D) 24 cm
Can anyone help me please?
The answer is B
4/30 = x/120
30x=480
480/30=16
x=16
Reply:4 cm=30 miles
120 miles = x
4/x=30/120
30x=480
30x=30=480/30
x=16 cm
Reply:Eh. you should be asking why the answer is what it is. B is the right answer, but because you have to cross multiply using a proportion. 4 = 30, 8 = 60, 16 = 120. Just doubled the values twice, or u can put then into a proportion/cross multiply...
Reply:16 cm. 120/30 = 4, 4 x 4 = 16
Reply:B
Reply:The answer is B.
Think about it: 4 cm = 30 miles.
Therefore 8 cm = 60 miles.
12 cm = 90 miles
16 cm = 120 miles
See? What grade are you in? You should have been able to figure that out. That is 2nd grade work.
Reply:The answer is 16 cm. 120m is four times thirty, so four times 4cm is 16.
A) 8 cm
B) 16 cm
C) 12 cm
D) 24 cm
Can anyone help me please?
The answer is B
4/30 = x/120
30x=480
480/30=16
x=16
Reply:4 cm=30 miles
120 miles = x
4/x=30/120
30x=480
30x=30=480/30
x=16 cm
Reply:Eh. you should be asking why the answer is what it is. B is the right answer, but because you have to cross multiply using a proportion. 4 = 30, 8 = 60, 16 = 120. Just doubled the values twice, or u can put then into a proportion/cross multiply...
Reply:16 cm. 120/30 = 4, 4 x 4 = 16
Reply:B
Reply:The answer is B.
Think about it: 4 cm = 30 miles.
Therefore 8 cm = 60 miles.
12 cm = 90 miles
16 cm = 120 miles
See? What grade are you in? You should have been able to figure that out. That is 2nd grade work.
Reply:The answer is 16 cm. 120m is four times thirty, so four times 4cm is 16.
Help me with some math questions.. TOTALLY important grade 9 math questions?
1. A map is drawn using a scale of 4 cm to represent 5 km
a) find the representative fraction
b) A road has a length of 9.4 cm on the map, find its actual distance in km
c) A lake has an area of 64 km*2 find its area represented on the map
2. a cylindrical container of radius 8 cm contains water to a height of 5 cm. Th water in this cylinder is then poured into another cylinder of radius 5 cm. what is the height of the water in the second cylinder?
3. the length and breadth of a rectangle are (2x+1)cm and (x-1)cm respectively. If the area of the rectangle is 90cm*2, form an equation in x and hence calculate the value of x.
just the answers will do,thanks so much you'll really help this is totally important
Help me with some math questions.. TOTALLY important grade 9 math questions?
"Just the answers will do"???????????????
Please do your own homework. If you don't know how to do it- asking for help with that would be more appropriate.
Reply:1.a.the representative fraction is :
1:1.25(i.e.,1cm=5/4km)
b.1 cm on the map is 1.25km
therefore, 9.4cm on the map is
9.4*1.25=11.75km
c.64km^2=%26gt;a square of sides 8 km each
8 km in the map will be
0.8*8=6.4 cm.
therefore a square with sides 6.4 cm is to be drawn
2. the volume in the first cylinder is equal to the volume in the
second cylinder.
pi*8*8*5=pi*5*5*h
320=25h
h=12.8cm
3.(2x+1)(x-1)=90
2x^2-x-91=0
x=7,(-26/4)
Reply:1 a) 4cm/5km=4cm/500000cm=1/125000 it is unitless
b) 9.4x125000cm or 9.4x1.25km=11.75km
c) 64=8x8/1.25x1.25=7.04cm*2
2.V1=pie X r*2 X h =3.14x64x5=1004.8cum
hence 1004.8=pie X r'*2 Xh
1004.8=3.14x25xh
h=1004.8/3.14x25
=100480/7850
=12.8cm
3. A= (2x+1)(x-1)=90
=2x*2-x-91=0
x=7
anemone
a) find the representative fraction
b) A road has a length of 9.4 cm on the map, find its actual distance in km
c) A lake has an area of 64 km*2 find its area represented on the map
2. a cylindrical container of radius 8 cm contains water to a height of 5 cm. Th water in this cylinder is then poured into another cylinder of radius 5 cm. what is the height of the water in the second cylinder?
3. the length and breadth of a rectangle are (2x+1)cm and (x-1)cm respectively. If the area of the rectangle is 90cm*2, form an equation in x and hence calculate the value of x.
just the answers will do,thanks so much you'll really help this is totally important
Help me with some math questions.. TOTALLY important grade 9 math questions?
"Just the answers will do"???????????????
Please do your own homework. If you don't know how to do it- asking for help with that would be more appropriate.
Reply:1.a.the representative fraction is :
1:1.25(i.e.,1cm=5/4km)
b.1 cm on the map is 1.25km
therefore, 9.4cm on the map is
9.4*1.25=11.75km
c.64km^2=%26gt;a square of sides 8 km each
8 km in the map will be
0.8*8=6.4 cm.
therefore a square with sides 6.4 cm is to be drawn
2. the volume in the first cylinder is equal to the volume in the
second cylinder.
pi*8*8*5=pi*5*5*h
320=25h
h=12.8cm
3.(2x+1)(x-1)=90
2x^2-x-91=0
x=7,(-26/4)
Reply:1 a) 4cm/5km=4cm/500000cm=1/125000 it is unitless
b) 9.4x125000cm or 9.4x1.25km=11.75km
c) 64=8x8/1.25x1.25=7.04cm*2
2.V1=pie X r*2 X h =3.14x64x5=1004.8cum
hence 1004.8=pie X r'*2 Xh
1004.8=3.14x25xh
h=1004.8/3.14x25
=100480/7850
=12.8cm
3. A= (2x+1)(x-1)=90
=2x*2-x-91=0
x=7
anemone
...maths...?
1) A map shows three towns A.B and C. Town A is due North of C. town B is due East of A. The distance Ac is 75km and the bearing of C from B is 245 degree. Calculate giving the answer to the nearest 100m:
(a) The distance AB
(b) The distance BC
2)Two boats X and Y, sailing in the race. Boat X is 145 due North of buoy B. Boat Y is due East of buoy B. Boat X and Y are 320m apart calculate:
(a) the distance BY
(b) the bearing of Y and X
(c) the bearing of X and Y
...maths...?
75 / sin 245* = X / sin25* So X(sin 245*) = 75(sin 25*) Then X =75(sin25*) / sin 245* Either using a chart or calculator do the rest. * = degrees. To figure BY you use the Pythagorean Therom which is A^2 + B^2 = C^2 or 320^2 = 145^2 + X^2 or approx 285 m 320/sin 90* = 285(sin x*) 320/ sin 90* =285 / sin x* 320 / 285 (sin 90*) = 1/ sin x* 320 (sin x*) / 285 (sin 90*) = 1 again use a chart or calc. to do the rest
Reply:A is the anwer of 1
2
a around 100 m
b 85
c 125
(a) The distance AB
(b) The distance BC
2)Two boats X and Y, sailing in the race. Boat X is 145 due North of buoy B. Boat Y is due East of buoy B. Boat X and Y are 320m apart calculate:
(a) the distance BY
(b) the bearing of Y and X
(c) the bearing of X and Y
...maths...?
75 / sin 245* = X / sin25* So X(sin 245*) = 75(sin 25*) Then X =75(sin25*) / sin 245* Either using a chart or calculator do the rest. * = degrees. To figure BY you use the Pythagorean Therom which is A^2 + B^2 = C^2 or 320^2 = 145^2 + X^2 or approx 285 m 320/sin 90* = 285(sin x*) 320/ sin 90* =285 / sin x* 320 / 285 (sin 90*) = 1/ sin x* 320 (sin x*) / 285 (sin 90*) = 1 again use a chart or calc. to do the rest
Reply:A is the anwer of 1
2
a around 100 m
b 85
c 125
Team Fortress 2 ... ?
What's your favorite map and why ?
I like 2Fort b/c I like being an engineer and that map has the best places to put those machines ! It's awesome b/c they never see it coming .. haha !
Team Fortress 2 ... ?
Dustbowl
cause its a bowl full of dust !
I like 2Fort b/c I like being an engineer and that map has the best places to put those machines ! It's awesome b/c they never see it coming .. haha !
Team Fortress 2 ... ?
Dustbowl
cause its a bowl full of dust !
Linear algebra (linear maps)?
IIf you guys could double check my work...i can't make it to my profs office hours and the homework is due the same day as the exam. No time to find out if i have no idea what i'm doing
or not.
V is a subspace of C(R) spanned by {1,x,e^-x,cos2x,sin2x}...These are linearly independent so are a basis.
The map is d/dx :V--%26gt; V
a. determine matrix representation [d/dx] with respect to the given basis.
sooo basically
d/dx: {1,x,e^-x,cos2x, sin2x} = {0,1,-e^-x, -2sin2x, 2cos2x}
and i figured it was a 5X5 matrix with
a11=0
a22 = 1
a33 = -e^-x
a44= -2*sin 2x
a55 = 2*cos 2x....the rest all zeros
b. Determine bases for the kernel and image.
Little confused here
So the kernal is the value of 1
so the basis is
{1,0,0,0,0}
The image is the rest of the values...so
{0,x,0,0,0}
{0,0,e^-x,0,0} ........ etc
or
i'll finish off in an additional note
Linear algebra (linear maps)?
sorry
or not.
V is a subspace of C(R) spanned by {1,x,e^-x,cos2x,sin2x}...These are linearly independent so are a basis.
The map is d/dx :V--%26gt; V
a. determine matrix representation [d/dx] with respect to the given basis.
sooo basically
d/dx: {1,x,e^-x,cos2x, sin2x} = {0,1,-e^-x, -2sin2x, 2cos2x}
and i figured it was a 5X5 matrix with
a11=0
a22 = 1
a33 = -e^-x
a44= -2*sin 2x
a55 = 2*cos 2x....the rest all zeros
b. Determine bases for the kernel and image.
Little confused here
So the kernal is the value of 1
so the basis is
{1,0,0,0,0}
The image is the rest of the values...so
{0,x,0,0,0}
{0,0,e^-x,0,0} ........ etc
or
i'll finish off in an additional note
Linear algebra (linear maps)?
sorry
UK Courier delivery zones (Business Post) mapped to UK postcodes?
Can someone please help by posting a list of UK delivery zones mapped to UK postcodes for Business Post?.
In particular looking to distinguish if some postcodes are in Zone B or Zone C in Scotland. They don't seem to have a table on their website - only a map.
Thanks.
UK Courier delivery zones (Business Post) mapped to UK postcodes?
Cant seem to know why you would want to know this information, as long as what you send gets there, each business post provider has different zonal idea's.
cyclamen
In particular looking to distinguish if some postcodes are in Zone B or Zone C in Scotland. They don't seem to have a table on their website - only a map.
Thanks.
UK Courier delivery zones (Business Post) mapped to UK postcodes?
Cant seem to know why you would want to know this information, as long as what you send gets there, each business post provider has different zonal idea's.
cyclamen
Need some help mapping addresses in Beijing?
We are considering an assignment in Beijing and need some help mapping addresses on the Google Map :
http://ditu.google.com/
1) ISB's Address
No. 10 An Hua Street
Shunyi District, Beijing 101318
The People's Republic of China
2) Western Academy of Beijing,
P.O. Box 8547,
10 Lai Guang Ying Dong Lu,
Beijing, 100103, P.R.C.
3) BISS
No.17, Area 4
Anzhen Xi Li
Chaoyang District
Beijing 100029
An individual link for each one would be great!
thanks
mbg
Need some help mapping addresses in Beijing?
1) http://www.isb.bj.edu.cn/
2) http://www.wab.edu/contact/directions.sh...
3) http://www.biss.com.cn/
Reply:i've already found the location by Google map, but dunno how to show you, as the URL does not change when you locate.
Here i got the translation of each of your addresses, you can just copy and paste them into the search bar of Google Map and check out.
1. 北京市 顺义区 安华街 10号
2. 北京市 来广营东路 10号 北京第二外国语大学
3. 北京市 朝阳区 安贞西里 4区 17号 BISS
Hope it will be helpful to you. if you want some further guidance, either about the Beijing city or the Chinese language, drop me a line.
http://ditu.google.com/
1) ISB's Address
No. 10 An Hua Street
Shunyi District, Beijing 101318
The People's Republic of China
2) Western Academy of Beijing,
P.O. Box 8547,
10 Lai Guang Ying Dong Lu,
Beijing, 100103, P.R.C.
3) BISS
No.17, Area 4
Anzhen Xi Li
Chaoyang District
Beijing 100029
An individual link for each one would be great!
thanks
mbg
Need some help mapping addresses in Beijing?
1) http://www.isb.bj.edu.cn/
2) http://www.wab.edu/contact/directions.sh...
3) http://www.biss.com.cn/
Reply:i've already found the location by Google map, but dunno how to show you, as the URL does not change when you locate.
Here i got the translation of each of your addresses, you can just copy and paste them into the search bar of Google Map and check out.
1. 北京市 顺义区 安华街 10号
2. 北京市 来广营东路 10号 北京第二外国语大学
3. 北京市 朝阳区 安贞西里 4区 17号 BISS
Hope it will be helpful to you. if you want some further guidance, either about the Beijing city or the Chinese language, drop me a line.
What's the difference between a mapped drive and shortcut to the server?
Hi
I am baffled by the reply I got from customer support for a software we use at the office.
Basically: What is the real value of mapping a drive versus sharing a folder?
Thanks
--------------------------------------...
Answer gotten: You need to run PI from a folder WITHIN a mapped drive letter, such as
X:\PI5, not directly from \\WIS-SERVER\PI5
Do this on the workstation (not WIS-SERVER) by selecting Map Network Drive
from the Tools menu in Explorer (or My Computer). Choose a drive letter,
select the shared drive (just sharing C: is easiest, though less secure) and
check the 'Reconnect at logon' checkbox. Now make sure your shortcut points
to the drive letter, not \\WIS-SERVER\PI5
Note: the PI5 folder must be contained WITHIN this shared drive or folder -
it will not work if PI is installed in the root. You may need to move the
PI installation on the server to C:\PI5\PI5, for example, and then share the
top-level PI5 folder.
What's the difference between a mapped drive and shortcut to the server?
as far as accessing the files there is no difference.
However, some programs require the mapped drive (in your example x:\P15). When the porgram was created the developers didn't give it the ability to use a UNC path (which is the \\WIS-SERVER). Therefore the software won't work that way.
Most newer programs dont' have a problem with \\WIS-Server, but older software will have issues with it.
Hope that helps.
Reply:The difference is that a mapped drive uses a mounted drive letter value, while the shortcut uses the UNC path... D:\ vs. \\
Depending on how they coded the application, it may not be able to deal with the UNC's.
I am baffled by the reply I got from customer support for a software we use at the office.
Basically: What is the real value of mapping a drive versus sharing a folder?
Thanks
--------------------------------------...
Answer gotten: You need to run PI from a folder WITHIN a mapped drive letter, such as
X:\PI5, not directly from \\WIS-SERVER\PI5
Do this on the workstation (not WIS-SERVER) by selecting Map Network Drive
from the Tools menu in Explorer (or My Computer). Choose a drive letter,
select the shared drive (just sharing C: is easiest, though less secure) and
check the 'Reconnect at logon' checkbox. Now make sure your shortcut points
to the drive letter, not \\WIS-SERVER\PI5
Note: the PI5 folder must be contained WITHIN this shared drive or folder -
it will not work if PI is installed in the root. You may need to move the
PI installation on the server to C:\PI5\PI5, for example, and then share the
top-level PI5 folder.
What's the difference between a mapped drive and shortcut to the server?
as far as accessing the files there is no difference.
However, some programs require the mapped drive (in your example x:\P15). When the porgram was created the developers didn't give it the ability to use a UNC path (which is the \\WIS-SERVER). Therefore the software won't work that way.
Most newer programs dont' have a problem with \\WIS-Server, but older software will have issues with it.
Hope that helps.
Reply:The difference is that a mapped drive uses a mounted drive letter value, while the shortcut uses the UNC path... D:\ vs. \\
Depending on how they coded the application, it may not be able to deal with the UNC's.
British Columbia forests? Need help, its for a project!?
Okay. so i have this geography book, and in it it says that british columbia has 'tempered humid' forests (mainly). Then i rented another book from the library about books from B.-C. and this book has a world map with all types of forests everywhere, and it says in B.-C. there are three kinds (order from most to least): the medditeranian forest, the aborded savana, rain forest and taiga (boreal forest) im sorry if some arent real forests im translating from french to english lol cuz i have history in french. Its just i want to know if the forest tempered humid has another name for one of the ones in my library book? and if not... then why doesnt my library book have it writen is it because theires so little of the tempered humid forest?
British Columbia forests? Need help, its for a project!?
BC has several types of forest.
1) Coastal Temperate Rainforest
2) Alpine Forests (Interior)
3) Boreal Forests
British Columbia forests? Need help, its for a project!?
BC has several types of forest.
1) Coastal Temperate Rainforest
2) Alpine Forests (Interior)
3) Boreal Forests
Linux hash examples?
It seems the last time I had to use a hash on Linux I was using C++ and was able to use the map class. I am now working in C and am not sure what is best to use.
I have read over http://linux.about.com/library/cmd/blcmd... but does anyone have a link or can directly provide me with some basic examples of creating a new hash, inserting elements, and retrieving data from the hash.
Thanks
Linux hash examples?
Using glib is probably a good idea, but if you want only a hash, then Uwe Ohse's strhash is a decent general purpose associative array library.
Small, liberally licensed, uses strings as keys.
No new release since 2003, but it still works just like back then.
http://www.ohse.de/uwe/strhash.html
Reply:Sure, take a look at some glib docs, such as:
http://www.ibm.com/developerworks/linux/...
wedding floral centerpieces
I have read over http://linux.about.com/library/cmd/blcmd... but does anyone have a link or can directly provide me with some basic examples of creating a new hash, inserting elements, and retrieving data from the hash.
Thanks
Linux hash examples?
Using glib is probably a good idea, but if you want only a hash, then Uwe Ohse's strhash is a decent general purpose associative array library.
Small, liberally licensed, uses strings as keys.
No new release since 2003, but it still works just like back then.
http://www.ohse.de/uwe/strhash.html
Reply:Sure, take a look at some glib docs, such as:
http://www.ibm.com/developerworks/linux/...
wedding floral centerpieces
?????????????????????????????/...
can someone help me with this?
i have to choose an answer.
The polar map gets its name from the fact that:
a) the axis runs through it
b) the equator is in the center of it
c) the North Pole or the South Pole is in the center of it
?????????????????????????????/...
Hmmm....I would say c, but im using only logic, not knowledge. Dont worry, one question wont kill ya, lol. good luck!
Reply:If i told you,it would be cheating..and plus, i didn't do well in school,my answer would be in correct hehe.
Reply:Polar refers to the Pole. Only one answer mentions the Pole, be it North or South, so that one must be correct. Answer C.
Hope this helps
i have to choose an answer.
The polar map gets its name from the fact that:
a) the axis runs through it
b) the equator is in the center of it
c) the North Pole or the South Pole is in the center of it
?????????????????????????????/...
Hmmm....I would say c, but im using only logic, not knowledge. Dont worry, one question wont kill ya, lol. good luck!
Reply:If i told you,it would be cheating..and plus, i didn't do well in school,my answer would be in correct hehe.
Reply:Polar refers to the Pole. Only one answer mentions the Pole, be it North or South, so that one must be correct. Answer C.
Hope this helps
Which term is also known as a meridian line?
a).geograophy b).longitude
c).hemisphere d).globe
e).equator f).map
g).prime h).meridian catographer
i).atitude j).map projection
Which term is also known as a meridian line?
B. longitude
Reply:b) longitude. Each line of longitude can also be called a meridian, and the Prime Meridian is a particular line of longitude passing through Greenwich, England.
Reply:A meridian is a line of longitude.
Think about the Prime Meridian. It is the point were longitude is measured.
Reply:I think its equator, or prime.
Reply:if my mind serves me correctly its b
c).hemisphere d).globe
e).equator f).map
g).prime h).meridian catographer
i).atitude j).map projection
Which term is also known as a meridian line?
B. longitude
Reply:b) longitude. Each line of longitude can also be called a meridian, and the Prime Meridian is a particular line of longitude passing through Greenwich, England.
Reply:A meridian is a line of longitude.
Think about the Prime Meridian. It is the point were longitude is measured.
Reply:I think its equator, or prime.
Reply:if my mind serves me correctly its b
Which term mark the beginning of longitude?
a).geograophy b).longitude
c).hemisphere d).globe
e).equator f).map
g).prime h).meridian catographer
i).atitude j).map projection
Which term mark the beginning of longitude?
Longitude scale starts at the PRIME MERIDIAN and goes east and west around the equator with 180 (the middle) being in the middle of the ocean.
Reply:Can't argue with the guy above me
2 pts!
c).hemisphere d).globe
e).equator f).map
g).prime h).meridian catographer
i).atitude j).map projection
Which term mark the beginning of longitude?
Longitude scale starts at the PRIME MERIDIAN and goes east and west around the equator with 180 (the middle) being in the middle of the ocean.
Reply:Can't argue with the guy above me
2 pts!
Which one of the below terms has 180 in each hemisphere?
a).geograophy b).longitude
c).hemisphere d).globe
e).equator f).map
g).prime h).meridian catographer
i).atitude j).map projection
Which one of the below terms has 180 in each hemisphere?
b) Longitude
Nothing else is anywhere near correct.
Reply:globe
Reply:i) attitude
as in "Do you want fries with that?"
bouquet
c).hemisphere d).globe
e).equator f).map
g).prime h).meridian catographer
i).atitude j).map projection
Which one of the below terms has 180 in each hemisphere?
b) Longitude
Nothing else is anywhere near correct.
Reply:globe
Reply:i) attitude
as in "Do you want fries with that?"
bouquet
Double integral help?
The region R is enclosed by the x axis and the three parabolas
x = (y^2/4) - 1
x = 1 - (y^2/4)
x = 4 - (y^2/16)
Note that R is the image of the rectangle a ≤ u ≤ b, 0 ≤ v ≤ c in the uv-plane under the map f = %26lt;x, y%26gt; = %26lt;u^2 - v^2, 2uv%26gt;.
Use f to do a coordinate change that will let you compute the following double integral.
∫∫ x dxdy
R
Double integral help?
Interesting. I would have done this by horizontal cross-sections:
Int {0 : y : 2, 1-y^2/4 : x : 4-y^2/16} x dx dy +
Int {2 : y : 4, y^2/4 - 1 : x : 4-y^2/16} x dx dy
The other approach you've suggested may provide a more elegant solution, but it's not familiar to me. So far, all I have is a=1, b=2, c=1. Here's my plan:
1) Take a small square (du by dv) in the uv-plane;
2) Run it through the transformation to find its xy-image;
3) Compute the area of that image, in terms of u and v;
4) Multiply by x=u^2-v^2;
5) Integrate.
Let's move up to step 3. The image of the small square is a nearly rectangular thing; we'd like to know how long its sides are.
Start with equations
x = u^2 - v^2, y = 2uv.
Take u and v partials:
x_u = 2u
y_u = 2v
These two give us the length of one side of the rectangle: Sqrt(4u^2 + 4v^2)
x_v = -2v
y_v = 2u
These two give us the length of the other side of the rectangle: Sqrt(4v^2 + 4u^2).
Happily, these are the same; thus, the area of the almost-rectangle is their product, 4u^2 + 4v^2. So,
dA = dx dy = 4(u^2+v^2) du dv.
We now multiply this by x = u^2-v^2 to get
∫∫ x dxdy = ∫∫ 4(u^2 + v^2)(u^2 - v^2) du dv
R
= 4 ∫∫ u^4 - v^4 du dv
= 4 ∫ [u^5 / 5 - uv^4]_1^2 dv
= 4 ∫ [6.2 - v^4] dv
= 4 [6.2 v - v^5 / 5]_0^1
= 4 [6.2 - .2]
= 24
Whew.
Edit: while checking this answer by way of my horizontal cross-section idea, I realized something.
Let region A be the one in question (in the first quadrant).
Let region B be the region bounded by x = 1- y^2/4 and x = y^2/4 - 1, for 2 %26lt; y %26lt; 4.
Let region C be the region bounded by y=0, y=4, x = 1 - y^2/4, x=4 - y^2/16.
Then (integral over A) + (integral over B) = (integral over C).
But region B is symmetric with respect to the y-axis, so (integral over B) = 0.
The integral over C has only one piece, which is nice. That integral works out to 24 as well, so at this point I'm pretty confident in my answer.
x = (y^2/4) - 1
x = 1 - (y^2/4)
x = 4 - (y^2/16)
Note that R is the image of the rectangle a ≤ u ≤ b, 0 ≤ v ≤ c in the uv-plane under the map f = %26lt;x, y%26gt; = %26lt;u^2 - v^2, 2uv%26gt;.
Use f to do a coordinate change that will let you compute the following double integral.
∫∫ x dxdy
R
Double integral help?
Interesting. I would have done this by horizontal cross-sections:
Int {0 : y : 2, 1-y^2/4 : x : 4-y^2/16} x dx dy +
Int {2 : y : 4, y^2/4 - 1 : x : 4-y^2/16} x dx dy
The other approach you've suggested may provide a more elegant solution, but it's not familiar to me. So far, all I have is a=1, b=2, c=1. Here's my plan:
1) Take a small square (du by dv) in the uv-plane;
2) Run it through the transformation to find its xy-image;
3) Compute the area of that image, in terms of u and v;
4) Multiply by x=u^2-v^2;
5) Integrate.
Let's move up to step 3. The image of the small square is a nearly rectangular thing; we'd like to know how long its sides are.
Start with equations
x = u^2 - v^2, y = 2uv.
Take u and v partials:
x_u = 2u
y_u = 2v
These two give us the length of one side of the rectangle: Sqrt(4u^2 + 4v^2)
x_v = -2v
y_v = 2u
These two give us the length of the other side of the rectangle: Sqrt(4v^2 + 4u^2).
Happily, these are the same; thus, the area of the almost-rectangle is their product, 4u^2 + 4v^2. So,
dA = dx dy = 4(u^2+v^2) du dv.
We now multiply this by x = u^2-v^2 to get
∫∫ x dxdy = ∫∫ 4(u^2 + v^2)(u^2 - v^2) du dv
R
= 4 ∫∫ u^4 - v^4 du dv
= 4 ∫ [u^5 / 5 - uv^4]_1^2 dv
= 4 ∫ [6.2 - v^4] dv
= 4 [6.2 v - v^5 / 5]_0^1
= 4 [6.2 - .2]
= 24
Whew.
Edit: while checking this answer by way of my horizontal cross-section idea, I realized something.
Let region A be the one in question (in the first quadrant).
Let region B be the region bounded by x = 1- y^2/4 and x = y^2/4 - 1, for 2 %26lt; y %26lt; 4.
Let region C be the region bounded by y=0, y=4, x = 1 - y^2/4, x=4 - y^2/16.
Then (integral over A) + (integral over B) = (integral over C).
But region B is symmetric with respect to the y-axis, so (integral over B) = 0.
The integral over C has only one piece, which is nice. That integral works out to 24 as well, so at this point I'm pretty confident in my answer.
Need help with some extra credit homework?
I'm taking a web page design class and the teacher gave us some extra credit homework. Of course the homework is optional but I need to bring up my grade a little bit so I need to do the extra credit. All these questions on the homework is stuff we haven't covered in class yet. The teacher told us that some of the answers can be found online. I've looked and I can't seem to find what I'm looking for so hopefully someone can help me figure this out.
4. To increase the capabilities of your browser, you can use an
A. plug-in
B. applet
C. embedded object
D. frame
5. The value ALIGN=BOTTOM aligns an image with the bottom of the _____ in which the image occurs.
A. page
B. paragraph
C. line
D. section
6. An image map works only with _____ protocol.
A. gopher
B. ftp
C. http
D. mailto
There are more questions and I will include them in additional details.
If you know of a website or something that can help me figure out these answers that would be greatly appreciated.
Need help with some extra credit homework?
Most of the above answers are incorrect, may be you can post your question at homework help websites like http://homeworkhelp.co.in/
Reply:4. a. plugin
5. c. line
6 c. http
9. A major disadvantage of a GIF animation file is that it
B. supports only 16 colors
14. You can immediately see a document you create in HTML if you use a
A. WYSIWYG editor (what you see is what you get)
18. The tag %26lt;H1%26gt; indicates
B. the most important heading
Hope that helps.
Reply:Just use google (Or yahoo) and type in the main subject in.
Like ALIGN=BOTTOM Image
or image map protocol.
it shouldn't take you long.
Reply:I would suggest checking out www.w3schools.com. It is the definitive site on web developing (HTML, etc) as it is maintained by the W3C consortium. Good luck : )
Reply:I would look up the definitions or context of each answer and then plug them into the question to see if they fulfill the question.
Reply:4.a.
5.d.
6.c.
9.b.
14.a.
18.b.
Good luck!
Reply:4) a
5) a
6) c
7) a
8) a
9) b
Not sure about 5, though
4. To increase the capabilities of your browser, you can use an
A. plug-in
B. applet
C. embedded object
D. frame
5. The value ALIGN=BOTTOM aligns an image with the bottom of the _____ in which the image occurs.
A. page
B. paragraph
C. line
D. section
6. An image map works only with _____ protocol.
A. gopher
B. ftp
C. http
D. mailto
There are more questions and I will include them in additional details.
If you know of a website or something that can help me figure out these answers that would be greatly appreciated.
Need help with some extra credit homework?
Most of the above answers are incorrect, may be you can post your question at homework help websites like http://homeworkhelp.co.in/
Reply:4. a. plugin
5. c. line
6 c. http
9. A major disadvantage of a GIF animation file is that it
B. supports only 16 colors
14. You can immediately see a document you create in HTML if you use a
A. WYSIWYG editor (what you see is what you get)
18. The tag %26lt;H1%26gt; indicates
B. the most important heading
Hope that helps.
Reply:Just use google (Or yahoo) and type in the main subject in.
Like ALIGN=BOTTOM Image
or image map protocol.
it shouldn't take you long.
Reply:I would suggest checking out www.w3schools.com. It is the definitive site on web developing (HTML, etc) as it is maintained by the W3C consortium. Good luck : )
Reply:I would look up the definitions or context of each answer and then plug them into the question to see if they fulfill the question.
Reply:4.a.
5.d.
6.c.
9.b.
14.a.
18.b.
Good luck!
Reply:4) a
5) a
6) c
7) a
8) a
9) b
Not sure about 5, though
Playstation Store Purchases??????????????????
Has anyone purchased stuff from the playstation store with a prepaid debit/credit card??? I want to know b/c I want the new maps for call of duty 4.
Playstation Store Purchases??????????????????
I use my debit card from my bank that takes funds from my checking account.
For the most part, if the card has a VISA or MasterCard logo on it, it's usable.
Reply:My husband has bought a couple games and extra stuff from the store with his credit card, with no problems.
Reply:yea lots of people do me and my friends buy games off it
Playstation Store Purchases??????????????????
I use my debit card from my bank that takes funds from my checking account.
For the most part, if the card has a VISA or MasterCard logo on it, it's usable.
Reply:My husband has bought a couple games and extra stuff from the store with his credit card, with no problems.
Reply:yea lots of people do me and my friends buy games off it
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